SOLUTION: PLEASE help me. I don't get it at all. I'm desperate :'( I've tried doing it so many time but I just don't get it. :'(
a9 - 1
A (a3 - 1)(a6 + a3 + 1)
B(a + 1)(a6 + a3 + 1)
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-> SOLUTION: PLEASE help me. I don't get it at all. I'm desperate :'( I've tried doing it so many time but I just don't get it. :'(
a9 - 1
A (a3 - 1)(a6 + a3 + 1)
B(a + 1)(a6 + a3 + 1)
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Question 766755: PLEASE help me. I don't get it at all. I'm desperate :'( I've tried doing it so many time but I just don't get it. :'(
a9 - 1
A (a3 - 1)(a6 + a3 + 1)
B(a + 1)(a6 + a3 + 1)
C(a - 1)(a2 - a - 1)(a6 + a3 + 1)
D(a - 1)(a2 + a + 1)(a6 + a3 + 1)
E (a3 + a + 1)(a6 + a3 + 1)
F cannot be factored
x8 - 16x4
A x4(x - 2)(x + 2)(x2 + 4)
B(x4 + 4x2)2
C(x4 - 4x2)2
D(x4 + 4x2)(x4 - 4x2)
E x4(x4 - 16)
F cannot be factored Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! There are special products that are probably shown as formulas in your textbook, and are useful in factoring. Some examples:
Square of a binomial: and
Cube of a binomial: and
Difference of squares:
Sum and difference of cubes: and
There is also taking out a common factor (if there is one), and factoring by parts (if applicable).
=
A
E is a factorization, but is not a factorization, because you can factor further
F cannot be factored
can be factored by parts:
At this point, you factor as a special product and get
E