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Question 766620: Hi there!
doing some homework and I need help.
A) Write the slope-intercept form of the equation of the line satisfying the
given conditions: perpendicular to 3x-4y= -1 and through (2,-1).
B) Write the slope-intercept form of the equation of the line satisfying the
given conditions: parallel to -2x-3y= -5 and through (-2,-3).
c) Write the slope-intercept form of the equation of the line satisfying the
given conditions: perpendicular to -3x+2y= -5 and through ( - 2, - 1 ).
d) Write the slope-intercept form of the equation of the line satisfying the
given conditions: parallel to 3x+4y= -1 and through ( 3, - 2 ).
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A) Write the slope-intercept form of the equation of the line satisfying the
given conditions: perpendicular to 3x-4y= -1 and through (2,-1).
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Find the slope of the line 3x-4y= -1
4y = 3x + 1
y = (3/4)x + 1/4
slope m = 3/4
Lines perpendicular have a slope that's the negative inverse
m = -4/3
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Use y = mx + b and the point to find b, the y-intercept.
-1 = (-4/3)*2 + b
b = 5/3
--> y = (-4/3)x + 5/3
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B) Write the slope-intercept form of the equation of the line satisfying the
given conditions: parallel to -2x-3y= -5 and through (-2,-3).
Similar to A
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These are all similar.
c) Write the slope-intercept form of the equation of the line satisfying the
given conditions: perpendicular to -3x+2y= -5 and through ( - 2, - 1 ).
d) Write the slope-intercept form of the equation of the line satisfying the
given conditions: parallel to 3x+4y= -1 and through ( 3, - 2 ).
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You do them, I'll check your answers.
PS Don't put spaces in the (x,y) for points. ( 3, - 2 ) --> (3,-2)
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