SOLUTION: a man is x years old which his son is y years old. the sum of their ages is twice the difference of their ages. if the product of their ages is 675, find the age of the man
Algebra ->
Absolute-value
-> SOLUTION: a man is x years old which his son is y years old. the sum of their ages is twice the difference of their ages. if the product of their ages is 675, find the age of the man
Log On
Question 766389: a man is x years old which his son is y years old. the sum of their ages is twice the difference of their ages. if the product of their ages is 675, find the age of the man Answer by subudear(62) (Show Source):
You can put this solution on YOUR website! Let age of man be x years and age of son is y years
x + y = 2 (x - y)
x + y = 2x - 2y
3y - x = 0 .....(1)
x*y = 675 ...(2)
replace value of y from equation (2) into (1)
3*(675/x) - x = 0
2025 - x^2 = 0
x^2 = 2025
x = sqrt(2025) = 45
age of man is 45 years
age of son is 15 years
(