SOLUTION: Please help me with this problem
If f(x) = 3^x, then f(x+1) - f(x) = ?
f(x) = 3^x
f(x+1) − f(x)
= 3^(x+1) − 3^x
= 3^x (3 − 1)
= 2 * f(x)
How did you
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-> SOLUTION: Please help me with this problem
If f(x) = 3^x, then f(x+1) - f(x) = ?
f(x) = 3^x
f(x+1) − f(x)
= 3^(x+1) − 3^x
= 3^x (3 − 1)
= 2 * f(x)
How did you
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Question 766372: Please help me with this problem
If f(x) = 3^x, then f(x+1) - f(x) = ?
f(x) = 3^x
f(x+1) − f(x)
= 3^(x+1) − 3^x
= 3^x (3 − 1)
= 2 * f(x)
How did you get 3^x (3 − 1) ??
Thank you so much Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! I will start from this point
= 3^(x+1) − 3^x
apply law of exponents 3^(x+1) = 3^x * 3
= 3^x * 3 - 3^x
= 3^x * (3 - 1)
= 2* 3^x
= 2* f(x)
