SOLUTION: Give all solutions of each nonlinear system of equations: x^2+y^2=9, |x|=|y|

Algebra ->  Systems-of-equations -> SOLUTION: Give all solutions of each nonlinear system of equations: x^2+y^2=9, |x|=|y|       Log On


   



Question 766249: Give all solutions of each nonlinear system of equations: x^2+y^2=9, |x|=|y|
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
 x²+y² = 9, 
   |x| = |y|

Square both sides of the second equation

    x² = y²

Substitute y² for x² in the first equation:

 y² + y² = 9
     2y² = 9
      y² = 9%2F2
       y = %22%22%2B-sqrt%289%2F2%29 = %22%22+%2B-+sqrt%289%29%2Fsqrt%282%29 = %22%22+%2B-+3%2Fsqrt%282%29 = %22%22+%2B-+3%2Fsqrt%282%29%22%22%2A%22%22sqrt%282%29%2Fsqrt%282%29 = %22%22+%2B-+3sqrt%282%29%2F2

And since x² = y², x also = %22%22+%2B-+3sqrt%282%29%2F2 

So the four possible solutions are:

(3sqrt%282%29%2F2,3sqrt%282%29%2F2), (3sqrt%282%29%2F2,-3sqrt%282%29%2F2), (-3sqrt%282%29%2F2,3sqrt%282%29%2F2), (-3sqrt%282%29%2F2,-3sqrt%282%29%2F2)

All four check, so all four are solutions.

The graph of x²+y²=9 is this circle


and the graph of |y|=|x| is the pair of graphs y = |x| and y = -|x|

 and

which together are



Put them together on the same graph and you get:



The four points of intersection are 

(3sqrt%282%29%2F2,3sqrt%282%29%2F2), (3sqrt%282%29%2F2,-3sqrt%282%29%2F2), (-3sqrt%282%29%2F2,3sqrt%282%29%2F2), (-3sqrt%282%29%2F2,-3sqrt%282%29%2F2)

Edwin