x²+y² = 9,
|x| = |y|
Square both sides of the second equation
x² = y²
Substitute y² for x² in the first equation:
y² + y² = 9
2y² = 9
y² =
y =
=
=
= 

=
And since x² = y², x also =
So the four possible solutions are:
(
,
), (
,
), (
,
), (
,
)
All four check, so all four are solutions.
The graph of x²+y²=9 is this circle
and the graph of |y|=|x| is the pair of graphs y = |x| and y = -|x|
and
which together are
Put them together on the same graph and you get:
The four points of intersection are
(
,
), (
,
), (
,
), (
,
)
Edwin