SOLUTION: 11) There are three consecutive even integers. 8/9 of the first nimber is 263 less than the sum of the second and third numbers. What are the integers?
Algebra ->
Absolute-value
-> SOLUTION: 11) There are three consecutive even integers. 8/9 of the first nimber is 263 less than the sum of the second and third numbers. What are the integers?
Log On
Question 766200: 11) There are three consecutive even integers. 8/9 of the first nimber is 263 less than the sum of the second and third numbers. What are the integers? Answer by solver91311(24713) (Show Source):
Let represent the first even integer. Then the second and third even integers are and .
Since is not an integer, you violate the initial assumption of the problem, therefore no solution. I suspect that you simply weren't paying attention to what you wrote as a problem statement, because this does work if you simply use consecutive integers rather than consecutive even integers.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it