SOLUTION: A bag contains 2 red balls, 3 green balls, 3 white balls, and 4 black balls. A random ball is removed and its color is recorded. The ball is returned to the bag, then another rando
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-> SOLUTION: A bag contains 2 red balls, 3 green balls, 3 white balls, and 4 black balls. A random ball is removed and its color is recorded. The ball is returned to the bag, then another rando
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Question 766021: A bag contains 2 red balls, 3 green balls, 3 white balls, and 4 black balls. A random ball is removed and its color is recorded. The ball is returned to the bag, then another random ball is removed. What is the probability that the first ball is white and the second ball is not green. Answer by solver91311(24713) (Show Source):
Add up the total number of balls in the bag. The probability that the first ball drawn is white is the number of white balls divided by the total number of balls. The probability of not green is the probability of white plus the probability of red plus the probability of black. The overall probabiltiy is the product of the two.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
