SOLUTION: how many gallons of a 90 antifreeze solution must be mixed with 100 gallons of 25 antifreeze to get a mixture that is 80% antifreeze
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Question 765808: how many gallons of a 90 antifreeze solution must be mixed with 100 gallons of 25 antifreeze to get a mixture that is 80% antifreeze
you need ___ gallons? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how many gallons of a 90 antifreeze solution must be mixed with 100 gallons of 25 antifreeze to get a mixture that is 80% antifreeze
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Equation::
0.90x + 0.25*100 = 0.80(x+100)
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90x + 25*100 = 80x + 80*100
10x = 55*100
x = 550 gallons (amt. of 90% solution needed)
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Cheers,
Stan H.
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