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| Question 765668:  Can someone help me with this problem?
 (5+i)/(3-2i)
 Possible answers:
 a)(15+2i)/(9-4i)
 b)(15-2i)/(3+2i)
 c)(13+13i)/13
 d)(13+13i)/13
 
 Answer by Lola77479(27)
      (Show Source): 
You can put this solution on YOUR website! Can someone help me with this problem? (5+i)/(3-2i)
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 That's not a problem, just an expression.
 You didn't say what you want to do.
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 Usually, it's "rationalize" the denominator, ie, make it a real number.  The possible answers indicate that, too, but it's your job to state what you want to do.
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 (5+i)/(3-2i)
 Multiply the NUM & DEN by the conjugate of the DEN, 3+2i
 = (5+i)*(3+2i)/((3-2i)*(3+2i)
 = (15 + 13i - 2)/(9+4)
 = (13 + 13i)/13
 = 1 + i
 
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