SOLUTION: Can someone help me with this problem? (5+i)/(3-2i) Possible answers: a)(15+2i)/(9-4i) b)(15-2i)/(3+2i) c)(13+13i)/13 d)(13+13i)/13

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Can someone help me with this problem? (5+i)/(3-2i) Possible answers: a)(15+2i)/(9-4i) b)(15-2i)/(3+2i) c)(13+13i)/13 d)(13+13i)/13       Log On


   



Question 765668: Can someone help me with this problem?
(5+i)/(3-2i)
Possible answers:
a)(15+2i)/(9-4i)
b)(15-2i)/(3+2i)
c)(13+13i)/13
d)(13+13i)/13

Answer by Lola77479(27) About Me  (Show Source):
You can put this solution on YOUR website!
Can someone help me with this problem?
(5+i)/(3-2i)
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That's not a problem, just an expression.
You didn't say what you want to do.
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Usually, it's "rationalize" the denominator, ie, make it a real number. The possible answers indicate that, too, but it's your job to state what you want to do.
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(5+i)/(3-2i)
Multiply the NUM & DEN by the conjugate of the DEN, 3+2i
= (5+i)*(3+2i)/((3-2i)*(3+2i)
= (15 + 13i - 2)/(9+4)
= (13 + 13i)/13
= 1 + i