Question 765651: Can someone help me with this problem?
(5+i)/(3-2i)
Possible answers:
a)(15+2i)/(9-4i)
b)(15-2i)/(3+2i)
c)(13+13i)/13
d)(13+13i)/13
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! To divide two complex numbers, multiply the quotient by
the form of ONE made from the complex conjugate of
the denominator, namely (3 + 2i)/(3 + 2i), so we have
(5+i)*(3+2i) / (3-2i)*(3+2i) which equals
(2i^2+13i+15) / (9-4i^2)
now that can be simplified by collecting like terms
in the numerator and replacing all i^2 with -1
to become
(2*(-1)+13i+15) / (9-4*(-1))
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(13i+13) / 13 is the answer!
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