SOLUTION: Please help with this problem: (5+i)/(3-2i) a)(15+2i)/(9-4i) b)(15-2i)/(3+2i) c)(13+13i)/13 d)(13+13i)/13 Thanks

Algebra ->  Absolute-value -> SOLUTION: Please help with this problem: (5+i)/(3-2i) a)(15+2i)/(9-4i) b)(15-2i)/(3+2i) c)(13+13i)/13 d)(13+13i)/13 Thanks      Log On


   

Question 765502: Please help with this problem:
(5+i)/(3-2i)
a)(15+2i)/(9-4i)
b)(15-2i)/(3+2i)
c)(13+13i)/13
d)(13+13i)/13
Thanks
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
You need only one piece of advice: Multiply numerator and denominator of items (a) and (b) by the conjugate of the denominator. Items (c) and (d) only use skills you have already learned so they are no chore. You already can understand %2813%2F13%29=1.

This is what happens when you multiply a complex number by its conjugate:

so in short,
%28a%2Bbi%29%28a-bi%29=a%5E2%2Bb%5E2