You can put this solution on YOUR website! 1+3+5+7+9+11+13+15+17+19=100
now pick any 5 digits which sum to 50
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The sum of 5 odd numbers cannot be even.
So at least one of the numbers must be even
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(n/2)(a + L) = 50
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(5/2)(a+L) = 50
a+L = 20
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7+9+10+11+13
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Cheers,
Stan H.