SOLUTION: 3) Aaron has two times as many pennies as nickles. If Aaron had nine more nickles and seven fewer pennies, he would have the same number of each coin. How many money does he have?
Algebra ->
Expressions-with-variables
-> SOLUTION: 3) Aaron has two times as many pennies as nickles. If Aaron had nine more nickles and seven fewer pennies, he would have the same number of each coin. How many money does he have?
Log On
Question 765008: 3) Aaron has two times as many pennies as nickles. If Aaron had nine more nickles and seven fewer pennies, he would have the same number of each coin. How many money does he have?
7) Jasmine's dimes and nickles total $5.25. If the dimes were replaced by nickles and nickles were replaced by dimes, then she would have $7.50. How many of each coin does she have? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! 3) Aaron has two times as many pennies as nickles. If Aaron had nine more nickles and seven fewer pennies, he would have the same number of each coin. How many money does he have?
let x=number of nickels
2x=number of pennies
x+9=2x-7
x=16
2x=32
number of nickels=16
number of pennies=32
..
7) Jasmine's dimes and nickles total $5.25. If the dimes were replaced by nickles and nickles were replaced by dimes, then she would have $7.50. How many of each coin does she have?
..
let n=number of nickels
let d=number of dimes
..
.05n+.10d=5.25
.10n+.05d=7.50
..
.10n+.20d=10.50
.10n+.05d=7.50
subtract
.15d=3.00
d=20
.05n=5.25-.10*d=5.25-2=3.25
n=3.25/.05=65
number of nickels=65
number of dimes=20