Question 76478: Solve the system by substitution.
3x-y=-7
x+y=-9
Answer by chitra(359)  (Show Source):
You can put this solution on YOUR website! The given system of equations are:
3x - y = -7 --------------(1)
x + y = -9 --------------(2)
EQN (2) can be written as: y = -9 - x substituting this is EQN (1), we get:
3x - (-9 - x) = -7
3x + 9 + x = -7
4x = - 7 - 9
4x = - 16
==> x = - 4
Substituting this in EQN(1)
3(-4) - y = -7
==> -12 - y = -7
==> -y = -7 + 12
==> - y = 5
==> y = -5
Hence, the solutions of the given set of equations are given by:
x = -4 and y = -5 are the solutions.
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