SOLUTION: If the sum of two numbers is 83 and the difference of the two numbers is 41, then the smaller number must be __

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Question 764774: If the sum of two numbers is 83 and the difference of the two numbers is 41, then the smaller number must be __
Found 2 solutions by lwsshak3, MathLover1:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
If the sum of two numbers is 83 and the difference of the two numbers is 41, then the smaller number must be __
***
let x=larger of two numbers
let y=smaller of two numbers
..
x+y=83
x-y=41
add:
2x=124
x=62
y=83-x=83-62=21
larger of two numbers=62
smaller of two numbers=21

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
let the greater number be x and the smaller number be y
if the sum is 83, then x%2By=83.....eq.1
and if the difference of the two numbers is 41,then x-y=41.....eq.2

to find the smaller number, solve the system:
x%2By=83.....eq.1
x-y=41.....eq.2
___________________________
x%2By=83.....eq.1....solve for x
x=83-y.....plug it in eq.2
83-y-y=41.....eq.2....solve for y
83-2y=41
83-41=2y
42=2y
42%2F2=y
highlight%2821=y%29....so, the smaller number is highlight%2821%29
now we can find greater number x
x=83-21
highlight%28x=62%29....the greater number is highlight%2862%29