SOLUTION:
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of si
Algebra ->
Finance
-> SOLUTION:
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of si
Log On
Question 764698:
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? Found 2 solutions by mananth, nuAge tutors:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Part A 14.00% per annum ------------- Amount invested =x
Paert B 11.00% per annum ------------ Amount invested = y
1390 Rs.0
Interest-----Rs. 3,508 for 2 years. So for 1 year 1754.00
Part A 14.00% per annum ---x
Paert B 11.00% per annum ---y
Total investment
x + 1 y= 13900 -------------1
Interest on both investments
14.00% x + 11.00% y= 1754
Multiply by 100
14 x + 11 y= 175400.00 --------2
Multiply (1) by -14
we get
-14 x -14 y= -194600.00
Add this to (2)
0 x -3 y= -19200
divide by -3
y = 6400
Part A 14.00% $ 7500
Paert B 11.00% $ 6400
You can put this solution on YOUR website! Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
100 100
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
(