SOLUTION: A chemist has 600 mL of solution that is 25% acid. She wants to make a solution that is 40% acid. How much acid should she add to the original solution?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A chemist has 600 mL of solution that is 25% acid. She wants to make a solution that is 40% acid. How much acid should she add to the original solution?       Log On


   

Question 764673: A chemist has 600 mL of solution that is 25% acid. She wants to make a solution that is 40% acid. How much acid should she add to the original solution?
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
{amount of pure acid}/{amount of solution}={concentration of adjusted solution}

L = 25%, concentration of available acid solution
T = 40% acid
R = 600, the volume ml. of available solution
v = ml. volume of 100% acid to add to get T as result. UNKNOWN.

%28L%2AR%2B100%2Av%29%2F%28R%2Bv%29=T
Solve for v.