SOLUTION: sandy has a collection of 57 coins worth $10. They consist of nickels, dimes, and quarters. The number of quarters is 2 more than 3 times the number of nickels. HOw many coins o
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Question 76441This question is from textbook College Algebra
: sandy has a collection of 57 coins worth $10. They consist of nickels, dimes, and quarters. The number of quarters is 2 more than 3 times the number of nickels. HOw many coins of each kind does she have?
I can't figure this out. Please help
on page 386 This question is from textbook College Algebra
You can put this solution on YOUR website! n+d+q=57...5n+10d+25q=1000...q=3n+2...substituting the value of q from the third equation into the first two equations gives
A)n+d+3n+2=57...and B)5n+10d+75n+50=1000..multiplying equation A by 10 and subtracting the result from equation B gives
5n+10d+75n+50-10n-10d-30n-20=1000-570...rearranging and combining terms gives...40n=400 or n=10...so q=32 and d=15
