SOLUTION: In the complex number system, solve 4x^2-2x+4=0
I am confused about the " solve using the complex number system", if I use the quadratic formula I get No real Solution, 1 +- (Squa
Question 764074: In the complex number system, solve 4x^2-2x+4=0
I am confused about the " solve using the complex number system", if I use the quadratic formula I get No real Solution, 1 +- (Square root of -60) over 4. I appreciate your help Answer by solver91311(24713) (Show Source):
That's right...there is no real solution. That means that the zeros are complex numbers rather than real numbers. Complex numbers are of the form where and are real numbers and is the imaginary number defined by . You also need to check your arithmetic.
So
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
