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Question 764024: Find the focus, directrix, and focal diameter of the parabola. 4x^2 +11y = 0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the focus, directrix, and focal diameter of the parabola. 4x^2 +11y = 0
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4x^2 +11y = 0
4x^2=-11y
x^2=-(11/4)y
This is an equation of a parabola that opens downward.
Its standard form: x^2=-4py
For given equation:
vertex: (0,0)
4p=11/4
p=11/16
focus: (0,11/16)
directrix: y=-11/16
I'm not familiar with the term "focal diameter" unless you mean focal width=4p=11/4
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