You really need to use parentheses to group things together. I have to assume that the in the LHS is part of the exponent on 2 since the problem isn't solvable algebraically otherwise. But for the sake of clear understanding you should have posted
2^(x+y) = 6^y
Going on that presumption
Note: The base you choose for the logarithm doesn't matter --
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
