SOLUTION: Two cyclists, 48 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of t
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Question 763749: Two cyclists, 48 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! You can think of one cyclist as standing still and
the other one approaching at the sum of their speeds
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Let = the speed of the slower one = the speed of the faster one
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The faster cyclist's speed is 18 mi/hr
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check answer:
Slower cyclist:
Faster cyclist:
OK
