SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t      Log On

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Question 763746: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1 hour 12 minutes. What is his speed in still air, and how fast is the wind blowing?
his speed=
wind speed=

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Distance equals rate times time, so distance divided by time is rate. With head wind, ground speed is air speed MINUS wind speed. With tail wind, ground speed is air speed PLUS wind speed.





Note: 6 minutes is 0.1 hour.

Solve the 2X2 system for and

John

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