Question 76370: Find 3 consective even intergers such that the sum of twice the first and three times the second minus the third equals -38.
Answer by ankor@dixie-net.com(22740)   (Show Source):
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:
Find 3 consecutive even integers,
x, (x+2), (x+4)
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the sum of twice the first and three times the second minus the third equals -38.
2x + 3(x+2) - (x+4) = - 38
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2x + 3x + 6 - x - 4 = -38
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2x + 3x - x = -38 - 6 + 4
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4x = -40
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x = -40/4
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x = -10
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The numbers: -10, -8, -6
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Check our solution of x = -10
sum of twice the first and three times the second minus the third equals -38.
2(-10) + 3(-8) - (-6) =
-20 - 24 + 6 = -38
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