SOLUTION: how do you factor these trinomials? 90x^2 - 143x + 56 and 132x^2 - 199x + 60 PLEASE help me!!!

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: how do you factor these trinomials? 90x^2 - 143x + 56 and 132x^2 - 199x + 60 PLEASE help me!!!       Log On


   



Question 76358: how do you factor these trinomials?
90x^2 - 143x + 56 and 132x^2 - 199x + 60
PLEASE help me!!!

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
see problem 76029 for details of a factoring technique

first equation...90*56=5040...factors to get -143 are -80 and -63...factors of 90 are 9 and 10...factors of 56 are -8 and -7

so 90x^2 - 143x + 56 = (10x - 7)(9x - 8)

second equation...132*60=7920...factors to get -199 are -144 and -55...factors of 132 are 11 and 12...factors of 60 are -5 and -12

so 132x^2 - 199x + 60 = (12x - 5)(11x - 12)