SOLUTION: how do you factor these trinomials? 90x^2 - 143x + 56 and 132x^2 - 199x + 60 PLEASE help me!!!
Algebra
->
Distributive-associative-commutative-properties
-> SOLUTION: how do you factor these trinomials? 90x^2 - 143x + 56 and 132x^2 - 199x + 60 PLEASE help me!!!
Log On
Algebra: Distributive, associative, commutative properties, FOIL
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Distributive-associative-commutative-properties
Question 76358
:
how do you factor these trinomials?
90x^2 - 143x + 56 and 132x^2 - 199x + 60
PLEASE help me!!!
Answer by
scott8148(6628)
(
Show Source
):
You can
put this solution on YOUR website!
see problem 76029 for details of a factoring technique
first equation...90*56=5040...factors to get -143 are -80 and -63...factors of 90 are 9 and 10...factors of 56 are -8 and -7
so 90x^2 - 143x + 56 = (10x - 7)(9x - 8)
second equation...132*60=7920...factors to get -199 are -144 and -55...factors of 132 are 11 and 12...factors of 60 are -5 and -12
so 132x^2 - 199x + 60 = (12x - 5)(11x - 12)