SOLUTION: in 5 years time a father will be twice as old as his son will be. four years ago he was three times as old as his son was. find their present ages?
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Question 763575: in 5 years time a father will be twice as old as his son will be. four years ago he was three times as old as his son was. find their present ages? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! in 5 years time a father will be twice as old as his son will be. four years ago he was three times as old as his son was. find their present ages?
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4 yrs ago:
x=son's age
3x=father's age
..
At present
x+4=son'age
3x+4=father's age
..
5 yrs from now:
x+4+5=x+9=son'age
3x+4+5=3x+9=father's age
3x+9=2(x+9)
3x+9=2x+18
x=9
son's present age=x+4=13
father's present age=3x+4=31
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