Question 763368: Two bikers ride away from each other in perpendicular paths.One biker rides 1 km/h faster than the other.They are 6km apart after one hour . Find the rate at which each person was biking /give answer to the nearest tenth
Found 2 solutions by ramkikk66, Alan3354:
Answer by ramkikk66(644)   (Show Source):
You can put this solution on YOUR website! Let one biker ride at x kmph
Then the other rides at x+1 kmph
At the end of one hour, the first has travelled x km, and the second has travelled x+1 km.
Since they are travelling perpendicular to each other, their paths form the two edges of a right triangle, and the hypotenuse is the distance between them. It is given that this hypotenuse is 6 km.
Applying Pythagoras theorem,
Edge1^2 + edge2^2 = hypotenuse^2
 Expanding, we get
 Simplifying, we get
Solving the above equation through the quadratic solver as shown below, we get the positive root as 3.713. So the 1st person is travelling at  kmph and the other at  kmph. Rounded off to the nearest 10th of a km.
:)
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
Discriminant d=284 is greater than zero. That means that there are two solutions:  .
Quadratic expression  can be factored:
Again, the answer is: 3.71307488658818, -4.71307488658818.
Here's your graph:
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Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! Two bikers ride away from each other in perpendicular paths.One biker rides 1 km/h faster than the other.They are 6km apart after one hour . Find the rate at which each person was biking /give answer to the nearest tenth
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The 2 legs will differ by 1 km
Solve for x
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