SOLUTION: Use vertices and asymptotes to graph the hyperbola. Find the equations of the asymptotes? x^2/9 - y^2/25 = 1

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Question 763200: Use vertices and asymptotes to graph the hyperbola. Find the equations of the asymptotes?
x^2/9 - y^2/25 = 1

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2F9+-+y%5E2%2F25+=+1

The axes of symmetry are the x- and y-axes.
You know that because if you replace -x for x,
or if you replace -y for y,
you get exactly the same equation.

If you make x=0 there is no solution for y meaning that x=0 never happens for the graph. In other words, it never crosses the y-axis, which is the x=0 line.
If you make highlight%28y=0%29 you find x%5E2%2F9=1 --> x%5E2=9,
with solutions highlight%28x=-3%29 and highlight%28x=3%29
Those are the vertices: (-3,0) and (3,0).

x%5E2%2F9+-+y%5E2%2F25+=+1 --> x%5E2%2F9+-+1+=+y%5E2%2F25 --> y%5E2%2F25=x%5E2%2F9+-+1 --> y%5E2%2Fx%5E2=25%281%2F9+-+1%2Fx%5E2%29 --> y%5E2%2Fx%5E2=25%2F9+-+25%2Fx%5E2%29
As abs%28x%29=sqrt%28x%5E2%29 increases, x%5E2 increases, and y%5E2%2Fx%5E2 approaches 25%2F9.
So y%5E2%2Fx%5E2=%28y%2Fx%29%5E2 approaches 25%2F9=%285%2F3%29%5E2
That means that the equations of the asymptotes are
highlight%28y=%285%2F3%29x%29 and highlight%28y=-%285%2F3%29x%29