SOLUTION: I stand on a building 640 feet high and throw a rock into the air with a velocity of 96 ft/sec. When does the rock have a height of 100 ft?

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Question 763173: I stand on a building 640 feet high and throw a rock into the air with a velocity of 96 ft/sec. When does the rock have a height of 100 ft?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I stand on a building 640 feet high and throw a rock into the air with a velocity of 96 ft/sec. When does the rock have a height of 100 ft?
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Use the common function for height vs time on Earth,
h%28t%29+=+-16t%5E2+%2B+96t+%2B+640 h in feet, t in seconds
h%28t%29+=+-16t%5E2+%2B+96t+%2B+640+=+100
16t%5E2+-+96t+-+540+=+0
4t%5E2+-+24t+-+135+=+0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 4x%5E2%2B-24x%2B-135+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-24%29%5E2-4%2A4%2A-135=2736.

Discriminant d=2736 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--24%2B-sqrt%28+2736+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-24%29%2Bsqrt%28+2736+%29%29%2F2%5C4+=+9.53834841531101
x%5B2%5D+=+%28-%28-24%29-sqrt%28+2736+%29%29%2F2%5C4+=+-3.53834841531101

Quadratic expression 4x%5E2%2B-24x%2B-135 can be factored:
4x%5E2%2B-24x%2B-135+=+%28x-9.53834841531101%29%2A%28x--3.53834841531101%29
Again, the answer is: 9.53834841531101, -3.53834841531101. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+4%2Ax%5E2%2B-24%2Ax%2B-135+%29

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Ignore the negative solution
t = 9.538 seconds