SOLUTION: log3(2x+3)=4-log3(x+0)solve for x log 3 = log subscript 3...I can't write it in the correct way sorry.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: log3(2x+3)=4-log3(x+0)solve for x log 3 = log subscript 3...I can't write it in the correct way sorry.       Log On


   

Question 763142: log3(2x+3)=4-log3(x+0)solve for x
log 3 = log subscript 3...I can't write it in the correct way sorry.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
log3(2x+3)=4-log3(x+0)solve for x
log%283%2C%282x%2B3%29%29%2Blog%283%2C%28x%2B0%29%29=4
log%283%2C%282x%2B3%29%28x%2B0%29%29=4
convert to exponential form
3^4=(2x+3)(x+0)
81=2x^2+3x
2x^2+3x-81=0
solve for x by quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=2, b=3, c=-81
ans:
x≈-7.158 (reject, x>0)
or
x≈5.658