SOLUTION: 7x^2+14x+21

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Question 76308: 7x^2+14x+21
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
7X^2+14X+21=0
USING THE QUADRATIC EQUATION WE GET FOR X:
ax^2+bx+c is the format using this solution:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(-14+-SQRT[14*14-4*7*21])/2*7
X=(-14+-SQRT[196-588])/14
X=(-14+-SQRT[-392])/14
(note any negative number has a sqrt of a number followed by i)
X=(-14+-19.8i)/14
X=(-14+19.8i)/14
X=-1+1.414i ANSWER.
X=(-14-19.8i)/14
X=-1-1.414i ANSWER.
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YOU APPARANTLY NEED TO WORK WITH THE QUADRATIC EQUATION METHOD OF SOLVING THESE TYPE OF PROBLEMS.