SOLUTION: Please help me solve this question: Amy needs to make 10L of 42% sulphuric acid solution. In the supply room , she finds bottles of 30% sulphuric acid solution and 60% sulphuric ac
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Question 762944: Please help me solve this question: Amy needs to make 10L of 42% sulphuric acid solution. In the supply room , she finds bottles of 30% sulphuric acid solution and 60% sulphuric acid solution. What volume of each solution should she mix in order to make the 42% solution ?
So far I have the two equations : x+y= 10
0.3x+0.6y=0.42 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Amy needs to make 10L of 42% sulphuric acid solution. In the supply room , she finds bottles of 30% sulphuric acid solution and 60% sulphuric acid solution. What volume of each solution should she mix in order to make the 42% solution ?
So far I have the two equations :
x+y= 10
0.3x+0.6y=0.42 ******
The 2nd equation is 0.3x + 0.6y = 0.42*10
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You can use:
x + y = 10
30x + 60y = 42*10
