SOLUTION: A man is paid P300 for each day he works and forfeits P80 for each day he is idle. At the end of 20 days he nets P5680. How many days did he work?

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Question 762875: A man is paid P300 for each day he works and forfeits P80 for each day he is idle. At the end of 20 days he nets P5680. How many days did he work?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = number of days he worked
+20+-+x+ = the number of days he was idle
-----------------
given:
+5680+=+300x+-+80%2A%28+20+-+x+%29+
+5680+=+300x+-+1600+%2B+80x+
+380x+=+5680+%2B+1600+
+380x+=+7280+
+x+=+19.158+
He worked 19.158 days
check:
+5680+=+300x+-+80%2A%28+20+-+x+%29+
+5680+=+300%2A19.158+-+80%2A%28+20+-+19.158+%29+
+5680+=+5747.368+-+80%2A.842+
+5680+=+5747.368+-+67.36+
+5680+=+5680.008+
OK -error must be due to rounding off