Question 762675: How do i graph this equation?
y=4/3x2+8/3x-8/3
Please give me the Vertex and 4 additional points, 2 on each side of the vertex so i can graph it.
Thanks!
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
The  -coordinate of the vertex of \ =\ ax^2\ +\ bx\ +\ c) is given by 
The  -coordinate of the vertex of , namely  , is given by the value of the function at  , namely:
\ =\ a(x_v)^2\ +\ b(x_v)\ +\ c) .
Now that you have the coordinates of the vertex, plot ) .
As it turns out, is an integer in this problem, so pick another value for that is 1 larger than . Evaluate the function at this value:
\ =\ a(x_v\,+\,1)^2\ +\ b(x_v\,+\,1)\ +\ c) .
Then plot \right)) . Use the property of symmetry to determine that if is a point on your graph, \right)) must also be on the graph.
Calculate  and repeat the above process for your other two points, giving you 5 points in all including the vertex.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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