Question 762551: four times a first number decreased by three times a second number is 22. the sum of the first number and twice the second number 0 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! four times a first number decreased by three times a second number is 22. the sum of the first number and twice the second number 0
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1st: a
2nd: b
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Equations:
4a-3b = 22
a + 2b = 0
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Substitute for "a" and solve for "b":
4(-2b)-3b = 22
-11b = 22
b = -2
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Solve for "a":
a = -2b
a = -2*-2 = 4
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Cheers,
Stan H.
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