Question 762314: the sum of three numbers is 25 The second is twice the first The third number exceed the second by 5. Find the number. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the sum of three numbers is 25 The second is twice the first The third number exceed the second by 5. Find the number.
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a + b + c = 25
b = 2a
c = b + 5
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Substgitute and solve for "b":
(b/2) + b + b+5 = 25
(5/2)b = 20
b = (2/5)20
b = 8
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a = (1/2)b = 4
c = b+5 = 13
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Cheers,
Stan H.
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