SOLUTION: A minor league baseball team plays 93 games in a season. If the team won 15 more than twice as many games as they lost, how many wins and losses did the team have?
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Question 762216: A minor league baseball team plays 93 games in a season. If the team won 15 more than twice as many games as they lost, how many wins and losses did the team have? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Games lost = x
Games won = (15 + 2x)
Total games played = Games won + Games lost.
93 = (15 + 2x) + x
93 = 15 + 3x
3x = 93 -15
3x = 78
x = 26
Games lost = 26
Games won = 67
Total 93
