SOLUTION: Solve the equation on the interval [0,360degrees] cos^2(t)+ 2cos(t)+1=0 help please so confused!

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Question 762213: Solve the equation on the interval [0,360degrees]
cos^2(t)+ 2cos(t)+1=0 help please so confused!
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Cos^2t + 2cost + 1 = 0
(Cost + 1)(Cost + 1)= 0
Cost = -1
t = 180 degrees
Hope this helps.
:-)