Question 762137: 4(x+1)<2x+3
Answer by 2897696(96)   (Show Source):
You can put this solution on YOUR website! 1) distribute 4 into ()
4x+1<2x+3
2) get variable by self, by moving the number to number side, and variable to variable side.
4x(-2x)+1< 2x(-2x)+3 move 2x to the other side by additive inverse.
2x+1(-1)<3(-1)move 1 to the other side by additive inverse
2x<2
3) divide 2 form x to get x by self
x<1
Answer: x<1
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