You can put this solution on YOUR website! x=1 upon 2-√ 3 =1/(2-√3)=(2+√3)/(2+√3)(2-√3)=(2+√3)/(4-3)=2+√3
so x-2=√3.............1
now x3-2x2-7x+5=x3-2x2-7x+14-14+5=x2(x-2)-7(x-2)-9=x2√3-7√3-9
-(2+√3)^2*√3-7√3-9=(4+3+4√3)√3-7√3-9=(7+4√3)√3-7√3-9=7√3+12-7√3-9=3