SOLUTION: During a chemistry experiment, the cork in a .5 foot tall beaker with an effervescent solution pops off with an ititial velocity of 20 feet per second. How many second does it tak

Algebra ->  Functions -> SOLUTION: During a chemistry experiment, the cork in a .5 foot tall beaker with an effervescent solution pops off with an ititial velocity of 20 feet per second. How many second does it tak      Log On


   

Question 76190: During a chemistry experiment, the cork in a .5 foot tall beaker with an effervescent solution pops off with an ititial velocity of 20 feet per second. How many second does it take for the cork to hit the table?
I need help in how to work out the problem. I believe I use the equation: y=Ax^2 + Bx + C.
Mitch
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the position (s) of an object moving under constant acceleration (a) with initial velocity (v) and initial position (p) in time (t) is s=%28at%5E2%29%2F2%2Bvt%2Bp

using 32ft/sec/sec as the gravitational acceleration s=-16t%5E2%2B20t%2B.5...the first term is negative because gravity acts downward

setting s=0 (cork on table) and solving for t gives...t=%28-20+%2B-+sqrt%2820%5E2-4%2A%28-16%29%2A.5%29%29%2F%282%2A%28-16%29%29...or t=%28-20+%2B-+sqrt%28432%29%29%2F%28-32%29...or t=.625+%2B-+.375+%28sqrt%283%29%29

so t approximately equals 1.27 sec.