SOLUTION: If a new rectangle has three times the length and width of the original rectangle, how would the perimeters and areas compare?
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Question 761807: If a new rectangle has three times the length and width of the original rectangle, how would the perimeters and areas compare? Answer by josgarithmetic(39625) (Show Source):
You can put this solution on YOUR website! Try just using variables for length and width.
y=length and w=width.
Original rectangle, perimeter = 2y+2w.
New rectangle according to 3y and 3w.
New perimeter = 2*3y+2*3w.
How do these compare?
New perimeter divided by original perimeter=
(