SOLUTION: Graph the line with slope 3 passing through the point (-2,-2)

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Question 761648: Graph the line with slope 3 passing through the point (-2,-2)
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
A linear equation can be expressed in the form y = mx + c where m is the slope and c is the y intercept (the value of y when x = 0, or the point where the line intersects the y axis)
Here, we know the slope m(3) and one instance of x and y (-2,-2). We don't know c.
By substituting for m,x and y we have
-2 = -2*3 + c
or c+=+4
So the line's equation is y+=+3x+%2B+4 or 3x+-+y+=+-4
See the graph below.
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 3+x+%2B+-1+y+=+-4 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-3%2F-1.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -4/3 = -1.33333333333333.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -4/-1 = 4.
  • Slope is -3/-1 = 3.
  • Equation in slope-intercept form: y=3*x+4.