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Question 761588: give 3 consecutive integers such that twice the first added to 5 times the second exceeds 3 times the third by 55
Answer by sachi(548)   (Show Source):
You can put this solution on YOUR website! let the 3 consecutive integers are a-1,a,a+1
such that twice the first added to 5 times the second exceeds 3 times the third by 55
2(a-1)+5a=3(a+1)+55
or 2a-2+5a=3a+3+55
or 4a=60
or a=15
so the 3 consecutive integers are 14,15,16
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