SOLUTION: the width of a rectangle is ten inches less than its length the perimeter of the rectangle is 112 what are the dimensions of the rectangle?
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Question 761558: the width of a rectangle is ten inches less than its length the perimeter of the rectangle is 112 what are the dimensions of the rectangle? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Length = x
Width = x - 10
Perimeter = 2* length + 2* width
112 = 2*x + 2*(x - 10)
112 = 2x + 2x - 20
4x = 112 + 20
4x = 132
x = 33ins
Length = 33ins
Width = 23ins
Hope this helps.
:-)
