SOLUTION: An object will take t seconds to drop d feet, where t= sqrt. d/16. What distance will the object drop in sqrt. 23/2 seconds? Please show details. Thank you :)

Algebra ->  Radicals -> SOLUTION: An object will take t seconds to drop d feet, where t= sqrt. d/16. What distance will the object drop in sqrt. 23/2 seconds? Please show details. Thank you :)       Log On


   

Question 761531: An object will take t seconds to drop d feet, where t= sqrt. d/16. What distance will the object drop in sqrt. 23/2 seconds?
Please show details. Thank you :)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An object will take t seconds to drop d feet, where t= sqrt. d/16. What distance will the object drop in sqrt. 23/2 seconds?
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t = sqrt(d/16)
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t^2 = d/16
d = 16t^2
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Your Problem:
d = 16(23/2)^2
----
d = 16(23^2)/4
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d = 4*23^2 = 2116 feet
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Cheers,
Stan H.
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