Question 761496: solve y=x^2-3 and 4x-y=6
Answer by unlockmath(1688)   (Show Source):
You can put this solution on YOUR website! Hello,
For this y=x^2-3 and 4x-y=6 let's substitute as follows:
4x-x^2+3=6
This can be rewritten as:
-x^2+4x+3=6
Subtract 6:
-x^2+4x-3=0
Pull out the negative:
-1(x^2-4x+3)=0
Now we can factor this to be:
-1(x-3)(x-1)=0
Solve for x:
x=3
x=1
Make sense?
RJ
www.math-unlock.com
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