SOLUTION: Find the equation of a line which passes through point (0, 9) and is perpendicular to the line formed by the equation 4x + 5y = -3. Express it in slope-intercept form.
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-> SOLUTION: Find the equation of a line which passes through point (0, 9) and is perpendicular to the line formed by the equation 4x + 5y = -3. Express it in slope-intercept form.
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Question 761157: Find the equation of a line which passes through point (0, 9) and is perpendicular to the line formed by the equation 4x + 5y = -3. Express it in slope-intercept form.
how do you do all of this ? i need visual steps, written ones confuse me. Answer by solver91311(24713) (Show Source):
Solve your given equation for in terms of everything else. The coefficient on in the resulting equation will be the slope of the given line. Take the negative reciprocal of that slope to get the slope of the desired line - because the slopes of perpendicular lines are negative reciprocals.
Then use the point-slope form of an equation of a line:
where are the coordinates of the given point and is the calculated slope.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
