SOLUTION: The lenght of a rectangle is 10 ft longer than twice the width.If the perimeter is 116 ft find the lenght and width of the rectangle.

Algebra ->  Test -> SOLUTION: The lenght of a rectangle is 10 ft longer than twice the width.If the perimeter is 116 ft find the lenght and width of the rectangle.      Log On


   



Question 760631: The lenght of a rectangle is 10 ft longer than twice the width.If the perimeter is 116 ft find the lenght and width of the rectangle.
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
l=2w+10
P=2(l+w)=116

so
l+w=58
2w+10+w=58

3w=48
w=16

l=2(16)+10=42

length: 42 ft
width: 16 ft